In a coil of resistance 10Ω, the induced current developed by changing magnetic flux through it, is shown in figure as a function of time. The magnitude of change in flux through the coil in Weber is?

As there is a change in flux, there will be a current generated. Which is given by,

Let the induced current be I and the resistance be R. Then the voltage across the coil is given by Ohm's Law:

V = IR

According to Faraday's law of electromagnetic induction, the induced EMF (voltage) is proportional to the rate of change of magnetic flux:

V = -dΦ/dt

Where:

• V is the induced voltage
• Φ is the magnetic flux
• t is the time

Combining these equations, we get:

IR = -dΦ/dt

dΦ = -IRdt

To find the total change in flux (ΔΦ), we need to integrate this equation over the time interval during which the current flows. The provided figure (which is missing from the input data) shows the current as a function of time. Let's assume the figure shows a rectangular pulse of current with magnitude I and duration Δt. Then the integral becomes:

ΔΦ = ∫ -IRdt = -IR∫dt = -IRΔt

Since R = 10Ω, and we need to determine ΔΦ using the current vs. time graph (which is absent from the provided data), we can't solve for a numerical answer without the visual data. The correct answer (4, 8, 6, or 2) would depend on the area under the I vs t curve (representing ∫Idt). The area under the curve represents the total charge that flows which is proportional to the change in magnetic flux according to the equation above. Therefore, the magnitude of the change in flux is equal to 10 times the area under the current versus time graph.