In a double slit experiment, when a thin film of thickness t having refractive index μ is introduced in front of one of the slits, the maximum at the centre of the fringe pattern shifts by one fringe width. The value of t is (λ is the wavelength of the light used)
λ2(μ-1)
λ(2μ-1)
2λ(μ-1)
λ(μ-1)
Solution:
Correct option is D. λ(μ-1) Shift = ΔX Width of one fringe = λ ΔX = (μ-1)t = 1λ For one maximum shift : t = λ/(μ-1)