In a double slit experiment, when light of wavelength 400 nm was used, the angular width of the first minima formed on a screen placed 1m away, was found to be 0.2°. What will be the angular width of the first minima, if the entire experimental apparatus is immersed in water?
0.266°
0.05°
0.1°
0.15°
Solution:
Correct option is B. 0.15° In air angular fringe width is given by θ_0 = λ/D Angular fringe width in water, θ_w = (λ/μ)/D = θ_0/μ=0.2°(4/3) = 0.15° Hence option B is correct answer