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Question:

In a hot water heating system, there is a cylindrical pipe of length 28 m and diameter 5 cm. Find the total radiating surface in the system.

Solution:

Given: H=28m, R=5/2=2.5cm=0.025m (2.5/100)
⇒CSA of pipe (cylindrical)=2πrh=2×22/7×0.025×28m2=4.4m2