1n3/2
1n3
1n
1n2
ΔE = hμ
The energy of an electron in a hydrogen-like atom is given by:
E = -13.6 Z²/n² eV
where Z is the atomic number and n is the principal quantum number.
For a transition from n to (n-1), the change in energy is:
ΔE = E(n-1) - E(n) = -13.6 Z²[(1/(n-1)²) - (1/n²)]
Since n>>1, we can approximate (n-1)² ≈ n²
ΔE ≈ -13.6 Z² [1/n² - 1/n²] = -13.6 Z² [n² - (n-1)²] / (n²(n-1)²) ≈ -13.6 Z² (2n -1) / n⁴
For large n, ΔE ≈ -13.6 Z² (2n) / n⁴ = -27.2 Z²/n³
Since ΔE = hμ, the frequency μ is proportional to ΔE:
μ ∝ 1/n³
Therefore, the frequency of radiation emitted is approximately proportional to 1/n³.