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Question:

In a LCR oscillatory circuit find the energy stored in inductor at resonance. If voltage of source is 10 V and resistance is 10Ω and inductance = 1H.

0.5 J

4 J

2 J

10 J

Solution:

Correct option is A. 0.5 J
Here, L = 1H, R = 10Ω, V = 10V
At resonance
Current in the circuit , I = V/R = 10/10 = 1 A
Energy Stored in inductor = (1/2)LI² = (1/2)(1)(1)² = 0.5 J.