In a population of 1000 individuals, 360 belong to genotype AA, 480 to Aa, and the remaining 160 to aa. Based on this data, the frequency of allele A in the population is?

According to Hardy-Weinberg equilibrium, the genetic variation in a population will remain constant from one generation to the next in the absence of disturbing factors.

Equation: p² + 2pq + q² = 1
where,
p² is the frequency of homozygous genotype AA
q² is the frequency of genotype aa
2pq is the frequency of genotype Aa

There are 1000 individuals, out of which 360 belong to genotype AA.
p² = 360/1000 = 0.36
Then p = √0.36 = 0.6.

So, the correct answer is '0.6'.