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Question:

In a series LCR circuit R=4Ω, XL=5Ω and XC=8Ω, the current leads the voltage by?

leads the voltage bytan⁻¹(3/5)

leads the voltage bytan⁻¹(3/4)

leads the voltage bytan⁻¹(5/9)

leads the voltage bytan⁻¹(5/8)

Solution:

φ=arctan(XL−XCR)
With the given values, we get
φ=arctan(5−84)=arctan(−34)
Thus, the current leads the voltage by tan⁻¹(3/4).