For α=0.36π degree, there will be destructive interference at point P.
For α=0.36π degree, there will be destructive interference at point O.
Fringe spacing depends on α.
For α=0, there will be constructive interference at point P.
Correct option is B. For α=0.36π degree, there will be destructive interference at point P. Δx=dsin α + dsin θ, α: small anglesin θ ≈ tan θ = y/b Δx=dα + dy/D (1) α=0 ∴ Δx=dy/D=0.3 × 11/1000=33 × 10⁻⁴mm Δx in terms of λ=33 × 10⁻⁴/600 × 10⁻⁶; λ=11λ/2 as Δx=(2n-1;)λ/2 There will be destructive interference (2) Δx=0.3mm × 0.36π × π/180 + 0.3mm × 11mm/1000=39 × 10⁻⁴mm 39 × 10⁻⁴=(2n-1) × 600 × 10⁻⁹ × 10³ 2n=7 There will be destructive interference (3) Δx=3mm × 0.36π × π/180 + 0=600nm 600nm=nλ n=1 constructive interference (4) Fringe width does not depend on α.