In an atom, the total number of electrons having quantum numbers n=4, |ml|=1 and ms=-1/2 are:
Solution:
n=4 l=0,1,2,3 |ml|=1 ⇒ ±1 ms=-1/2 For l=0, ml=0 l=1, ml=-1,0,+1 l=2, ml=-2,-1,0,+1,+2 l=3, ml=-3,-2,-1,0,+1,+2,+3 So, six electrons can have |ml|=1 ms=-1/2 (two each in p, d and f subshell).