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Question:

In an experiment for determining the gravitational acceleration g of a place with the help of a simple pendulum, the measured time period square is plotted against the string length of the pendulum in the figure. What is the value of g at the place?

9.91 m/s2

10.0 m/s2

9.81 m/s2

9.87 m/s2

Solution:

Using, The expression for the time period of a pendulum, T = 2π(l/g)^0.5
T² = 4π²l/g
Thus, the slope of the graph gives, the value of 4π²/g
Hence, slope is 4 for the graph given.
Thus, the value of g is 9.87