The end correction in this experiment is 0.9cm
The resonance at 50.7cm corresponds to the fundamental harmonic
The speed of sound determined from this experiment is 332ms⁻¹
The wavelength of the sound wave is 66.4cm
Let n₁ be the harmonic corresponding to 50.7cm, n₂ the harmonic corresponding to 83.9cm. Since both are consecutive harmonics, their difference = λ/2 ∴ λ/2 = (83.9 – 50.7)cm λ/2 = 33.2cm λ = 66.4cm λ/4 = 16.6cm
Length corresponding to fundamental mode must be close to λ/4. 50.7cm must be closed to an odd multiple of this length as 16.6 × 3 = 49.8cm. therefore 50.7 is 3rd harmonic
e + 50.7 = 3λ/4 e = 49.8 – 50.7 = -0.9cm
Speed of sound, v = fλ ∴v = 500 × 66.4cm/sec = 332.000m/s.
Hence, Option (A), (B) and (C) are correct