104
107
1010
103
The ratio is given by the formula:
( \frac{n_1}{n_2} = \frac{e^{-\frac{E_g}{kT_1}}}{e^{-\frac{E_g}{kT_2}}} = e^{-E_g(\frac{1}{kT_1} - \frac{1}{kT_2})} )
Where:
Substituting the values:
( \frac{n_1}{n_2} = e^{-1.2eV(\frac{1}{8.617 \times 10^{-5} \times 600} - \frac{1}{8.617 \times 10^{-5} \times 300})} )
( \frac{n_1}{n_2} = e^{-1.2(\frac{1}{0.0517} - \frac{1}{0.02586})} \approx e^{-1.2(19.33 - 38.66)} \approx e^{23.196} \approx 1.176 \times 10^{10} )
Therefore, the ratio of the number of charge carriers at 600 K and 300 K is of the order of 10^10.