In ΔABC, right-angled at B, AB=24cm, BC=7cm. Determine: (i) sinA, cosA (ii) sinC, cosC

∠B=90°
AC²=AB²+BC².. (Pythagoras theorem)
AC²=(24)²+(7)²
AC=25
(i)sinA=BC/AC=7/25, cosA=AB/AC=24/25
(ii)sinC=AB/AC=24/25, cosC=BC/AC=7/25