Area of Shaded region=2×Area of segment BC(or Segment AC)+Area of circle with diameter DO
Since, DO=OC=BO=AO=7cm
∴Area of segment BC=Area of quadrant BOC−Area of ΔBOC=(π×7×7/4)−(1/2×7×7)=14cm²
Area of circle with diameter OD=π×3.5×3.5=38.5cm²
∴Area of Shaded region=(2×14)+38.5=66.5cm²