devarshi-dt-logo

Question:

In Fig., ABC and AMP are two right triangles, right angled at B and M respectively. Prove that: (i) ∆ABC ≅ ∆AMP (ii) CA/PA = BC/MP

Solution:

In ∆ABC and ∆AMP, ∠ABC = ∠AMP = 90°
∠A is common
∴By AA criterion of similarity, ∆ABC ≅ ∆AMP
∴CA/PA = BC/MP (Corresponding Sides of Similar Triangles)
Hence Proved