In Fig., ABC is a quadrant of a circle of radius 14 cm and a semicircle is drawn with BC as diameter. Find the area of the shaded region.

Area of shaded region = Area of △ABC + Area of semicircle with diameter BC − Area of quadrant ABC
∴ Area of △ABC = 1/2 × 14 × 14 = 98 cm²
In △ABC, by Pythagoras theorem, BC = 14√2
∴ Area of semicircle with diameter BC = π × r²/2 = 1/2 × 22/7 × 7 × 7 × 2 = 154 cm²
Area of quadrant ABC = π × r²/4 = 1/4 × 22/7 × 14 × 14 = 154 cm²
∴ Area of shaded region = 98 + 154 − 154 = 98 cm²