In figure, OABC is a square of side 7 cm. If OAPC is a quadrant of a circle with centre O, then find the area of the shaded region. [Use π=22/7].

Given that OABC is a square of side 7 cm
Therefore, Area of square OABC = (7)² cm² = 49 cm²
Also, it is given that OAPC is a quadrant of a circle with centre O.
Radius of the quadrant of the circle = OA = 7 cm
Therefore, Area of the quadrant of circle = (1/4)(πr²) = (1/4)(π × 7²) = 49π/4 = 49 × 22 / 4 × 7 = 77/2 cm²
Therefore, Area of the shaded region = Area of Square − Area of Quadrant of circle.
= 49 − 77/2 = 98 − 77 / 2 = 21/2 ⇒ 10.5 cm²
So, the area of the shaded region is 10.5 cm²