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Question:

In graphite and diamond, the percentage of p-characters of the hybrid orbitals in hybridisation are respectively _________.

67and75

33and75

33and25

50and75

Solution:

In graphite, carbon atoms are sp2 hybridized. The sp2 hybrid orbitals have one s orbital and two p orbitals. Therefore, the percentage of p-character is (2/3) * 100% = 66.67% ≈ 67%.

In diamond, carbon atoms are sp3 hybridized. The sp3 hybrid orbitals have one s orbital and three p orbitals. Therefore, the percentage of p-character is (3/4) * 100% = 75%.

Therefore, the percentage of p-characters of the hybrid orbitals in graphite and diamond are respectively 67% and 75%. The correct option is 67 and 75.