In Process 1, the energy stored in the capacitor EC and heat dissipated across resistance ED are related by:
EC=2ED
EC=12ED
EC=ED
EC=EDln2
Solution:
The correct option is CEC=ED Potential difference Vacross capacitor C, and charge q are related as V=qC Final charge on the capacitor is CV Wb=CV2 EC=12CV2 ED=Wb−ΔEC=CV2 12CV2=12CV2 Hence EC=ED