devarshi-dt-logo

Question:

In Process 1, the energy stored in the capacitor EC and heat dissipated across resistance ED are related by:

EC=2ED

EC=12ED

EC=ED

EC=EDln2

Solution:

The correct option is CEC=ED
Potential difference Vacross capacitor C, and charge q are related as V=qC
Final charge on the capacitor is CV
Wb=CV2
EC=12CV2
ED=Wb−ΔEC=CV2
12CV2=12CV2
Hence EC=ED