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Question:

In Process 2, total energy dissipated across the resistance ED is:

ED=13(12CV20)

ED=3CV20

ED=3(12CV20)

ED=12CV20

Solution:

ED=Wb−ΔVED=CV03[V)3+2V)3+V0]⅓CV20ED=CV0[2V0]3⅓CV20=CV206Hence D is correct answer.