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Question:

In SI units, the dimensions of √(ε₀μ₀) is

A⁻¹TML³

AT²M⁻¹L⁻¹

A²T³M⁻¹L⁻²

AT⁻³ML³/²

Solution:

Correct option is B. A²T³M⁻¹L⁻²
Dimension of ε₀μ₀
[ε₀] = [M⁻¹L⁻³T⁴A²]
[μ₀] = [MLT⁻²A⁻²]
dimension of ε₀μ₀ = [M⁻¹L⁻³T⁴A²MLT⁻²A⁻²]
¹/² = [M⁻²L⁻⁴T⁶A⁴]¹ = [M⁻¹L⁻²T³A²].