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Question:

In the circuit shown below, the key K is closed at t = 0. The current through the battery is:

VR2att=0andVR1R2√R21+R22att=∞

V(R1+R2)R1R2att=0andVR2att=∞

VR1R2√R21+R22att=0andVR2att=∞

VR2att=0andV(R1+R2)R1R2att=∞

Solution:

At t=0, inductor behaves like an infinite resistance. Therefore, no current flows through the inductor branch. The current through the battery is given by V/(R1+R2) at t=0. As t approaches infinity, the inductor behaves like a short circuit, so the current through the battery is V/R2.