In the circuit shown in the figure identify the equivalent gate of the circuit and make its truth table.
Solution:
The three gates in the circuit are NAND gate. So, the output are as shown in figure. Here Y = ¬A'.B' = ¬¬A.¬B = ¬¬A + ¬¬B = A + B (by de Morgan theorem) Hence, the equivalent gate will be OR gate and the truth table is shown in figure.