A⋅B
A⋅¬B + ¬A⋅B
A⋅B + A⋅B
A+B
The correct option is A⋅¬B + ¬A⋅BOutput of AND gates are A⋅¬B and ¬A⋅B. Hence output of NOR gate will be A⋅¬B + ¬A⋅B.