In the figure, find the area of the shaded region, enclosed between two concentric circles of radii 7cm and 14cm where ∠AOC = 40°. Consider π = 22/7.

Given: Radius of inner circle = 7cm
Radius of outer circle = 14cm
Angle made by sector = 40°
Area of sector OAC = (40°/360°) × πr² = (1/9) × (22/7) × 14² = 68.44
Area of sector OBD = (40°/360°) × πr² = (1/9) × (22/7) × 7² = 17.11
Area of the small region ABDC = Area of the small sector OAC - Area of the small sector OBD = (68.44 - 17.11)cm²
Area of shaded region ABDC = Area of outer circle - Area of inner circle - area of small region ABCD
Area of shaded region ABDC = π × 14² - π × 7² - (68.44 - 17.11)cm²
Area of shaded region ABDC = 616 - 154 - 51.33 cm² = 410.67 cm²