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Question:

In the following reaction, xA → yB, log₁₀(-d[A]/dt) = log₁₀(d[B]/dt) + 0.3010. 'A' and 'B' respectively can be:

n-Butane and Iso-butane

C₂H₄ and C₄H₈

N₂O₄ and NO₂

C₂H₂ and C₆H₆

Solution:

The correct option is B (C₂H₄ and C₄H₈)

log(-d[A]/dt) = log(d[B]/dt) + 0.3010
-d[A]/dt = 2 × d[B]/dt
1/2 × -d[A]/dt = d[B]/dt
2A → B
2C₂H₄ → C₄H₈