In the given circuit, a charge of +80µC is given to the upper plate of the 4 µF capacitor. Then in the steady state, the charge on the upper plate of the 3 µF capacitor is?
+48µC
+40µC
+32µC
+80µC
Solution:
Let q be the charge on the 3µF capacitor. Then 80 - q / 2 = q / 3 q = 48µC