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Question:

In the given circuit diagram, the currents I1 = 0.3A, I4 = 0.8A and I5 = 0.4A are flowing as shown. The currents I2, I3 and I6 respectively, are:

0.4A, 1.1A, 0.4A

1.4A, 0.4A, 1.1A

1.1A, 0.4A, 0.4A

1.1A, 1.4A, 0.4A

Solution:

The correct option is C (1.1A, 0.4A, 0.4A)
From KCL, I3 = 0.8 - 0.4 = 0.4A
I2 = 0.4 + 0.4 + 0.3 = 1.1A
I6 = 0.4A