In the given circuit diagram when the current reaches steady state in the circuit, the charge on the capacitor of capacitance C will be :
CEr1(r1+r)
CE
CEr2(r+r2)
CEr1(r2+r)
Solution:
At steady state, no current will flow through the capacitor. Current through the battery: i = E/(r + r2) Potential diff. across P2: V = ir2 V = Er2/(r + r2) Thus charge on capacitor: Q = CV Q = CEr2/(r + r2)