In the given circuit, the charge on 4µF capacitor will be:

Correct option is B. 24µC
So total charge flow=q=5.4µF × 10V=54µC
The charge will be distributed in the ratio of capacitance ⇒q1/q2=2.4/3=4/5
⇒9X=54µC ⇒X=6µC
⇒Charge on 4µF capacitor will be=4X=4 × 6µC=24µC