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Question:

In the given circuit, the voltage across the load is maintained at 12V. The current in the zener diode varies from 0-50 mA. What is the maximum wattage of the diode?

12 W

6 W

1.2 W

0.6 W

Solution:

The voltage drop across the diode and the load are the same because they are connected in parallel. The maximum current through the diode is 50 mA. Thus, the maximum power dissipated in the diode will be 50 mA times 12 V = 0.6 W