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Question:

In the given figure, if △ABE ≅ △ACD, show that △ADE ∼ △ABC.

Solution:

Given △ABE ≅ △ACD
∴ AB = AC (1)
Also, AE = AD (2)
From (1) and (2), AB/AD = AC/AE and ∠A is common
∴ By SAS Criterion of Similarity, △ADE ∼ △ABC [hence proved]