In the ground state of Cu+, the number of shells occupied, sub-shells occupied, filled orbitals and unpaired electrons respectively are: [Atomic no. of copper = 29]
4,8,15,0
4,7,14,2
3,6,15,1
3,6,14,0
Solution:
Cu+=1s²2s²2p⁶3s²3p⁶3d¹⁰ Shells occupied=3(n=1,2,3), Subshells occupied=6 Filled orbitals=14(1+1+3+1+3+5) Unpaired electrons=0 Hence, the correct answer is option A.