445.33
35.33
43.33
37.33
10 ml of 1M H2SO4 corresponds to 10 mmol.
It will neutralize 20 mmol of NH3.
Weight of N = 14 × 20/1000 g = 0.280 g.
Thus 0.75 g of sample of organic compound contains 0.280 g of nitrogen.
The percentage of nitrogen in the organic sample is 0.280/0.75 × 100 = 37.33