CH3−CH=CH−CHO
CH3−CH2−CH2−CH2−OH
CH3−CH2−CH2−CH3
CH3COCH3
In the reaction sequence, 2CH3CHO + OH⁻ → A Δ → B; the product B is CH3−CH=CH−CHO.
2CH3CHO + OH⁻ → CH3−CH(OH)CH2−CHO (A)
Δ → CH3−CH=CH−CHO (B)
In presence of hydroxide ions, two moles of acetaldehyde condense to form beta-hydroxy alcohol (compound A) which on dehydration forms alpha beta-unsaturated aldehyde (compound B). Thus option (A) is correct.