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Question:

In which case will the particle move in a straight line with constant velocity?

(IV)(i)(S)

(III)(iii)(P)

(II)(iii)(S)

(III)(ii)(R)

Solution:

The correct option is A(II)(iii)(S)
Fnet=Fe+FB⇒F=qE+qv×B
For particle to move in a straight line, Fnet=zero
Hence qE+qv×B=0