In ΔPQR, right-angled at Q, PR+QR=25cm and PQ=5cm. Determine the values of sinP, cosP and tanP.

Given, PR+QR=25, PQ=5
Let PR=x
∴QR=25-x
PR²=PQ²+QR².. (Pythagoras theorem)
x²=(5)²+(25-x)²
x²=25+625+x²-50x
50x=650
x=13
∴PR=13
QR=25-13=12
sinP=QR/PR=12/13
cosP=PQ/PR=5/13
tanP=QR/PQ=12/5