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Question:

Initially spring in its natural length. Now a block of mass 0.25 kg is released. Find the maximum force by the system on the floor.

15 N

25 N

30 N

20 N

Solution:

Correct option is C. 25 N
Work-energy theorem on (0.25)kg
(1/2)Kx² = mgx
Kx = 2mg
Kx = 2 × 0.25 × 10 = 5 N
N = kx + 2g = 5 + 20 = 25 N.