(2,-1)
(-2,1)
(2,1)
(-2,-1)
Note that 7-6x-x² = 16-(x+3)² and d/dx(7-6x-x²) = -6x-2x = -2(3+x)
So, we have
∫2x+5√(7-6x-x²)dx = ∫2x+6√(7-6x-x²)dx - ∫1√(16-(x+3)²)dx = -2√(7-6x-x²) - sin⁻¹((x+3)/4) + C
So, we have A=-2, B=-1. Thus option D is the correct answer.