Let ABC be a right triangle in which AB = 6 cm, BC = 8 cm and ∠B = 90°. BD is the perpendicular from B on AC. The circle through B, C, D is drawn. Construct the tangents from A to this circle.

Construct the triangle ABC and BD ⊥ AC. Then draw a circle with centre O such that BO = OC = 4 cm. Join the point O and A and locate M be the midpoint of AO. And draw a circle with centre M and radius = MO = AM. Let this circle cuts the previous circle at P and Q. Now join AP and AQ which are the desired tangents.