π/6
5π/6
π/2
2π/3
w = √3 + i/2 = eiπ/6
So wn = ei(nπ/6)
Now, for z1, cos(nπ/6) > 1/2 and for z2, cos(nπ/6) < -1/2
Possible positions of z1 are A1, A2, A3 whereas of z2 are B1, B2, B3 (as shown in the figure)
So, possible value of ∠z1Oz2 according to the given options is 2π/3 or 5π/6