f(2)<1−loge2
g(1)>1−loge2
f(2)>1−loge2
g(1)<1−loge2
f'(x)=e^(f(x)−g(x))g'(x) ∀x∈R ⇒e^−f(x)f'(x)−e^−g(x)g'(x)=0 ⇒∫(e^−f(x)f'(x)−e^−g(x)g'(x))dx=C ⇒−e^−f(x)+e^−g(x)=C ⇒−e^−f(1)+e^−g(1)=−e^−f(2)+e^−g(2) ⇒−e^−1+e^−g(1)=−e^−f(2)+e^−1 ⇒e^−f(2)+e^−g(1)=2e^−1 ⇔e^−f(2)<2e^−1 and e^−g(1)<2e^−1 ⇒−f(2)<loge2 and −g(1)<loge2 ⇒f(2)>1−loge2 and g(1)>1−loge2.