Let f(x) = 5 - |x - 2| and g(x) = |x + 1|, x ∈ R. If f(x) attains maximum value of α and g(x) attains minimum value at β, then limx→αβ(x - 1)(x² - 5x + 6)/(x² - 6x + 8) is equal to
-3/2
1/2
-1/2
3/2
Solution:
Correct option is A. 1/2 Maxima of f(x) occurred at x = 2 i.e. α = 2 Minima of g(x) occurred at x = -1 i.e. β = -1 ∴ limx→2(-1)(x - 1)(x - 2)(x - 3)/(x - 2)(x - 4) = 1/2.