π/2
π/4
π/6
π/3
Given that c and d are Perpendicular
∴ c . d = 0
Putting values ⇒ 5|^a|^2 + 6^a.^b - |^b|^2 = 0
⇒ 6^a . ^b = -5
⇒ ^a . ^b = -5/6 = |^a||^b|cosθ = -1/2
Since ^a and ^b are Unit vectors
So, cosθ = -1/2
∴ θ = π/3
Hence, option 'D' is correct.