Let I = ∫ba (x⁴ - 2x²) dx. If I is minimum, then the ordered pair (a, b) is?

Let f(x) = x²(x² - 2) = x²(x - √2)(x + √2)
As long as f(x) lies below the x-axis, the definite integral will remain negative, so the correct value of (a, b) is (-√2, √2) for the minimum of I.