Let L be the line passing through the point P(1,2) such that its intercepted segment between the co-ordinate axes is bisected at P. If L1 is the line perpendicular to L and passing through the point (-2,1), then the point of intersection of L and L1 is: (1120,2910) (310,175) (35,2310) (45,125)

Let the equation of line L be xa+yb=1
Line cuts x-axis at A(a,0) and (0,b)
Since, the intercepted segment between the axes is bisected at P. So, coordinates of P are (a2,b2)
Given coordinates of P≡(1,2)⇒a2=1,b2=2⇒a=2,b=4
Equation of line L is x2+y4=1
4x+2y=4
2x+y=2
Slope of L, m=−2
Slope of L1, m1=−1m=12
Equation of line L1 passing through (−2,1) and slope 12
y−1=12(x+2)
2y−2=x+2
x−2y+4=0
Solving equation of L and L1:
2x+y=2
x−2y=−4
Multiplying equation (1) by 2 and subtracting equation (2):
4x+2y=4
x−2y=−4
5x=0
x=0
y=2
Point of intersection is (0,2)