Let f(x) = x|x| and g(x) = sinx. Statement 1: gof is differentiable at x=0 and its derivative is continuous at that point. Statement 2: gof is twice differentiable at x=0. Choose the correct option:

g(f(x))=sin(f(x))=sin(x²), x≥0
-sin(x²), x<0
(g(f(x)))'=2xcos(x²),x≥0
-2xcos(x²),x<0
gof is differentiable at x=0 and its derivative is continuous at that point.
R.H.D. of (g(f(0)))'=lim(h→0⁺)2hcosh²/h=0
L.H.D. of (g(f(0)))'=lim(h→0⁻)-2hcos(h²)/h=0
Clearly gof is twice differentiable at x=0.
Therefore, Statement 1 is true, Statement 2 is true, Statement 2 is a correct explanation for Statement 1
Hence, option 'B' is correct.