Let PS be the median of the triangle with vertices P(2,2), Q(6,-1) and R(7,3). The equation of the line passing through (1,-1) and parallel to PS is 2x+9y+7=0, 2x-y=0, 4x+7y+3=0, 4x-y=0

According to the question, PS is the median of the triangle so S is the midpoint of Q and R. i.e, S((13/2,1)), P(2,2)
Slope of PS = (1-2)/(13/2-2) = -1/(9/2) = -2/9
As the line passing through (1, -1) is parallel to PS, its slope will be equal to PS
Equation will be y-(-1)/x-1 = -2/9
9(y+1) = -2(x-1)
9y+9 = -2x+2
9y+9+2x-2 = 0
2x+9y+7 = 0