𝐜 = x𝐚 + y𝐛 + 𝐚 × 𝐛𝐜 ⋅ 𝐚 = x and x = 2cosα𝐜 ⋅ 𝐛 = y and y = 2cosαAlso, |𝐚 × 𝐛| = 1∴ 𝐜 = (2cosα)(𝐚 + 𝐛) + 𝐚 × 𝐛∴ |𝐜|² = 4cos²α(𝐚 + 𝐛)² + (𝐚 × 𝐛)² + 2cosα(𝐚 + 𝐛) ⋅ (𝐚 × 𝐛)∴ 4 = 8cos²α + 1∴ 8cos²α = 3